If the pH of pure water is to be adjusted to pH = 4.9 with acid, the amount of hydrogen chloride can be calculated as follows: -lg [H +] = 4.9 [H +] = 10 ^ -4.9 = 10 ^ 0.1 * 10 ^ -5.0 = 1.26 * 10 ^ -5mol / L; The required mass of hydrogen chloride is: 36.5g * 1.26 * 10 ^ -5 = 46 * 10 ^ -5g = 0.46mg The amount of hydrochloric acid converted into 36% is 0.46mg * 100 / 36 = 1.3mg.
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